[tex](2q {}^{2} r {}^{3} ) {}^{ - 6} = ..........[/tex]
[tex]a. \: 2 {}^{ - 6} q {}^{ - 4} r {}^{ - 3} [/tex]
[tex]b. \: 2 {}^{ - 6} q {}^{ 8} r {}^{ 9} [/tex]
[tex]c. \: \frac{1}{64q {}^{8} {r}^{9} } [/tex]
[tex]c. \: \frac{1}{64q {}^{12} {r}^{18} } [/tex]
Jawaban:
[tex]\bold{d.\: \frac{1}{64q {}^{12} {r}^{18} }} [/tex]
Penjelasan dengan langkah-langkah:
[tex](2q {}^{2} r {}^{3} ) {}^{ - 6} \\ \\ = \frac{1}{(2q {}^{2} r {}^{3} ) {}^{ 6} } \\ \\ = \frac{1}{ { {2}^{6}{q}^{2 \times 6} {r}^{3 \times 6} }} \\ \\ = \frac{1}{64 {q}^{12} {r}^{18} } [/tex]
Penjelasan dengan langkah-langkah:
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Nyatakan dalam pangkat positif
[tex]\boxed{\bf a^{-n} = \frac{1}{a^n}}[/tex]
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[tex]\tt \left(2q^2 r^3 \right)^{-6}[/tex]
[tex]= \tt \left(\dfrac{1}{2q^2 r^3}\right)^6[/tex]
[tex]= \tt \dfrac{1^6}{2^6 \times q^{2 \times 6} \times r^{3 \times 6}}[/tex]
[tex]= \tt \dfrac{1}{64q^{12} r^{18}} \: \text{[Opsi D]}[/tex]
[answer.2.content]
